BÀI TẬP CÁC CT CON

Tiêu đề: BÀI TẬP CÁC CT CON Wed Apr 23, 2008 7:23 pm

Code:: #include<conio.h>
#include<stdio.h>
#include<math.h>
double TongS24A(int n);
//============================
void main()
{
int n;
char ch;
double s=0;
do
{
   printf("\n\t CT Tinh Tong S=1+2+3+...+n");
   printf("\n\t Moi Nhap Gia Tri N:");
   scanf("%d",&n);
   s=TongS24A(n);
   printf("\n\t Neu N=%d,Thi Ket Qua S=%14.0f",n,s);
   printf("\n\t Ban Co Muon Tie1p Tuc Hok (C/K)");
   ch=getch();
}
while((ch=='C')||(ch=='c'));
getch();
}
//=================================
double TongS24A(int n)
{
double s=0;
for(int i=1;i<=n;i++)
s+=i;
return s;
}

Code:: #include<conio.h>
#include<stdio.h>
#include<math.h>
double GT24B(int n);
//============================
void main()
{
int n;
char ch;
double gt=1;
do
{
   printf("\n\t CT Tinh GT S=n!");
   printf("\n\t Moi Nhap Gia Tri N:");
   scanf("%d",&n);
   gt=GT24B(n);
   printf("\n\t Neu N=%d,Thi Ket Qua S=%14.0f",n,gt);
   printf("\n\t Ban Co Muon Tie1p Tuc Hok (C/K)");
   ch=getch();
}
while((ch=='C')||(ch=='c'));
getch();
}
//=================================
double GT24B(int n)
{
double gt=1;
for(int i=1;i<=n;i++)
gt*=i;
return gt;
}

Code:: #include<conio.h>
#include<stdio.h>
#include<math.h>
double LT24C(int n,int x);
//============================
void main()
{
int n,x;
char ch;
double lt=1;
do
{
   printf("\n\t CT Tinh GT S=n!");
   printf("\n\t Moi Nhap Gia Tri X:");
   scanf("%d",&x);
   printf("\n\t Moi Nhap Gia Tri N:");
   scanf("%d",&n);
   lt=LT24C(n,x);
   printf("\n\t Neu X=%d,N=%d,Thi Ket Qua S=%14.0f",x,n,lt);
   printf("\n\t Ban Co Muon Tiep Tuc Hok (C/K)");
   ch=getch();
}
while((ch=='C')||(ch=='c'));
getch();
}
//=================================
double LT24C(int n,int x)
{
double lt=1;
for(int i=1;i<=n;i++)
lt*=x;
return lt;
}

Code:: #include<conio.h>
#include<stdio.h>
#include<math.h>
double GT24D(int n);
//============================
void main()
{
int n;
char ch;
double s=1,gt=1;
do
{
   printf("\n\t CT Tinh GT S=1+3!+5!+....(2*n+i)!!");
   printf("\n\t Moi Nhap Gia Tri N:");
   scanf("%d",&n);
   s=GT24D(n);
   printf("\n\t Neu N=%d,Thi Ket Qua S=%14.0f",n,s);
   printf("\n\t Ban Co Muon Tie1p Tuc Hok (C/K)");
   ch=getch();
}
while((ch=='C')||(ch=='c'));
getch();
}
//=================================
double GT24D(int n)
{
double s=1,gt=1;
for(int i=1;i<=n;i++)
{
   gt=gt*(2*i)*(2*i+1);
   s=s+gt;
}
return s;
}

Code:: #include<conio.h>
#include<stdio.h>
#include<math.h>
double LT24E(int n,int x);
//============================
void main()
{
int n,x;
char ch;
double lt=x,s=x;
do
{
   printf("\n\t CT Tinh GT S=X+X^3+X^5+....+X^(2*n+i)");
   printf("\n\t Moi Nhap Gia Tri X:");
   scanf("%d",&x);
   printf("\n\t Moi Nhap Gia Tri N:");
   scanf("%d",&n);
   lt=LT24E(n,x);
   printf("\n\t Neu X=%d,N=%d,Thi Ket Qua S=%14.0f",x,n,lt);
   printf("\n\t Ban Co Muon Tiep Tuc Hok (C/K)");
   ch=getch();
}
while((ch=='C')||(ch=='c'));
getch();
}
//=================================
double LT24E(int n,int x)
{
double lt=x,s=x;
for(int i=1;i<=n;i++)
{
lt=lt*x*x;
s=s+lt;
}
return s;
}

Code:: #include<conio.h>
#include<stdio.h>
#include<math.h>
double GT24F(int n);
//============================
void main()
{
int n;
char ch;
double s=1,gt=1;
do
{
   printf("\n\t CT Tinh GT S=1-3!+5!+....(-1)*(2*n+i)!!");
   printf("\n\t Moi Nhap Gia Tri N:");
   scanf("%d",&n);
   s=GT24F(n);
   printf("\n\t Neu N=%d,Thi Ket Qua S=%14.0f",n,s);
   printf("\n\t Ban Co Muon Tie1p Tuc Hok (C/K)");
   ch=getch();
}
while((ch=='C')||(ch=='c'));
getch();
}
//=================================
double GT24F(int n)
{
double s=1,gt=1;
int d=-1;
for(int i=1;i<=n;i++)
{
   gt=gt*(2*i)*(2*i+1);
   s=s+d*gt;
d=-d;
}
return s;
}

Code:: #include<conio.h>
#include<stdio.h>
#include<math.h>
double LT24G(int n,int x);
//============================
void main()
{
int n,x;
char ch;
double lt=x,s=x;
do
{
   printf("\n\t CT Tinh GT S=X-X^3+X^5+....+(-1)*X^(2*n+i)");
   printf("\n\t Moi Nhap Gia Tri X:");
   scanf("%d",&x);
   printf("\n\t Moi Nhap Gia Tri N:");
   scanf("%d",&n);
   lt=LT24G(n,x);
   printf("\n\t Neu X=%d,N=%d,Thi Ket Qua S=%14.0f",x,n,lt);
   printf("\n\t Ban Co Muon Tiep Tuc Hok (C/K)");
   ch=getch();
}
while((ch=='C')||(ch=='c'));
getch();
}
//=================================
double LT24G(int n,int x)
{
int d=-1;
double lt=x,s=x;
for(int i=1;i<=n;i++)
{
lt=lt*x*x;
s=s+d*lt;
d=-d;
}
return s;
}

Code:: #include<conio.h>
#include<stdio.h>
#include<math.h>
double T24H(int n,int x);
//============================
void main()
{
int n,x;
char ch;
double lt=x,s=x,gt=1;
do
{
   printf("\n\t CT Tinh GT S=X-X^3/3!+X^5/5!+....+(-1)*X^(2*n+i)/(2*n+i)!");
   printf("\n\t Moi Nhap Gia Tri X:");
   scanf("%d",&x);
   printf("\n\t Moi Nhap Gia Tri N:");
   scanf("%d",&n);
   s=T24H(n,x);
   printf("\n\t Neu X=%d,N=%d,Thi Ket Qua S=%f",x,n,s);
   printf("\n\t Ban Co Muon Tiep Tuc Hok (C/K)");
   ch=getch();
}
while((ch=='C')||(ch=='c'));
getch();
}
//=================================
double T24H(int n,int x)
{
double lt=x,s=x,gt=1;
for(int i=1;i<=n;i++)
{
lt=lt*x*x;
gt=gt*(2*i)*(2*i+1);
s=s+lt/gt;

}
return s;
}

Tiêu đề: Re: BÀI TẬP CÁC CT CON Wed Apr 23, 2008 9:31 pm

lưu ý Tong S phải viết liền vô ko dc viết cách ra => vầy mới đúng TongS... những cái khác cũng vậy

Tiêu đề: Re: BÀI TẬP CÁC CT CON Sun Apr 27, 2008 11:35 pm

Code:: #include<conio.h>
#include<stdio.h>
#include<math.h>
double Sinx(int x);
//==============================
void main()
{
char ch;
int x,i,d;
double gt,gt1,lt,lt1;
long n;
float sin,dk;
do
{
printf("\n\t CT Tinh Goc Sin X");
printf("\n\t Moi Nhap Goc X:");
scanf("%d",&x);
sin=Sinx(x);
printf("\n\t Neu GT=%f,LT=%f,Thi dk=%14.0f",gt,lt,dk);
printf("\n\t Neu X=%d,Thi SinX=%14.12f",x,sin);
printf("\n\t Ban Co Muon Tiep Tuc Hok (C/K):");
ch=getch();
}
while((ch=='c')||(ch=='C'));
getch();
}
//=================================
double Sinx(int x)
{
int i,d;
double gt,gt1,lt,lt1;
long n;
float sin,dk;
   lt = x;
   gt = 1;
   n = 1;
   dk = x;
   while(dk >= 0.00001)
   {
      n = n + 1;
      lt = lt * x;
      gt = gt * n;
      dk = lt / gt;
   }
   lt1 = x;
   gt1 = 1;
   sin = x;
   d = -1;
   for (i = 1; i <= n; i++)
   {
      lt1 = lt1 * x * x;
      gt1 = gt1 * (2 * i) * (2 * i + 1);
      sin = sin + d * lt1/gt1;
      d = -d;
   }
   return sin;
}